MCQ
Ultraviolet radiations of $6.2 \mathrm{eV}$ falls on an aluminium surface (work function $4.2 \mathrm{eV}$ ). The kinetic energy in joules of the fastest electron emitted is approximately
  • A
    $3.2 \times 10^{-21}$
  • $3.2 \times 10^{-19}$
  • C
    $3.2 \times 10^{-17}$
  • D
    $3.2 \times 10^{-15}$

Answer

Correct option: B.
$3.2 \times 10^{-19}$
$ K_{\max }(\mathrm{eV})=E(\mathrm{eV})-W_0(\mathrm{eV})=6.2-4.2=2 \mathrm{eV} $
$ \therefore K_{\max }(\text { Joules })=2 \times 1.6 \times 10^{-19} \mathrm{~J}=3.2 \times 10^{-19} \mathrm{~J}$

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