MCQ
Uncertainity in position of an electron and helium atom is same. If uncertainity in momentum of electron is $32 \times 10^5$  then uncertainity in momentum of helium atom is
  • $32 \times 10^5$
  • B
    $16 \times 10^5$
  • C
    $8 \times 10^5$
  • D
    $4 \times 10^5$

Answer

Correct option: A.
$32 \times 10^5$
a
According to Heisenberg's Uncertainity principle:

$\Delta x . \Delta p \geq h / 4 \pi$

therefore for a known amount of uncertainty in position, all particles will have same uncertainty in momentum. given $\Delta p_{e}=32 \times 10^{5}$

thus, $\Delta p_{H e}=32 \times 10^{5}$

option A is correct

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