MCQ
Under a pressure head the rate of orderly volume flow of a liquid through a capillary tube is $Q$ . If the length of capillary tube is doubled and the diameter of tube is halved, the rate of flow would become
  • $\frac {Q}{32}$
  • B
    $\frac {Q}{8}$
  • C
    $\frac {Q}{4}$
  • D
    $8Q$

Answer

Correct option: A.
$\frac {Q}{32}$
a
$\mathrm{Q}=\frac{\pi \mathrm{Pr}^{4}}{8 \mathrm{n} \ell}$

$\frac{Q^{\prime}}{Q}=\left(\frac{r_{2}}{r_{1}}\right)^{4}\left(\frac{\ell_{1}}{\ell_{2}}\right)$

$Q^{\prime}=\left(\frac{1}{2}\right)^{4}\left(\frac{1}{2}\right)^{4} Q=\frac{Q}{32}$

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