Question
Using divisibility tests, determine if $639210$ is divisible by $6.$
✓
Answer
A number is divisible by $6$ if it is divisible by $2 \ \& \ 3$ both.
$i.$ Divisible by $2$
$\because$ Unit's digit $= 0$
$\therefore$ $639210$ is divisible by $2.$
$ii.$ Divisibility by $3$
Sum of the digit $= 6 + 3 + 9 + 2 + 1 + 0 = 21,$
which is divisible by $3$
$\therefore$ $639210$ is divisible by $3$
Since, $639210$ is divisible by $2$ and $3$ both, so it is divisible by $6.$
$i.$ Divisible by $2$
$\because$ Unit's digit $= 0$
$\therefore$ $639210$ is divisible by $2.$
$ii.$ Divisibility by $3$
Sum of the digit $= 6 + 3 + 9 + 2 + 1 + 0 = 21,$
which is divisible by $3$
$\therefore$ $639210$ is divisible by $3$
Since, $639210$ is divisible by $2$ and $3$ both, so it is divisible by $6.$
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