Question
Using factor theorem, factorize the following polynomials:
$2y^3 - 5y^2 - 19y + 42$

Answer

Let $f(y)=2 y^3-5 y^2-19 y+42$ be the given polynomial.
Now, putting $y=2$, we get
$f(2)=2(2)^3-5(2)^2-19(2)+42$
$=16-20-38+42$
$=-58+58=0$
Therefore, $(y-2)$ is a factor of polynomial $f(y)$.
Now,
$f(y)=2 y^2(y-2)-y(y-2)-21(y-2)$
$=(y-2)\left(2 y^2-y-21\right)$
$=(y-2)\left(2 y^2-7 y+6 y-21\right)$
$=(y-2)(y+3)(2 y-7)$
Hence $(y-2),(y+3)$ and $(2 y-7)$ are the factors of polynomial $f(y)$.

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