Question
Using Raoult’s law explain how the total vapour pressure over the solution is related to mole fraction of components in the following solutions.
CHCl3(l) and CH2Cl2(l)

Answer

For a binary solution having both components as volatile liquids (viz. CHCl3 and CH2Cl2), the total pressure will be
$\text{p}=\text{p}_1=\text{x}_1\text{p}^0_1+\text{x}_2\text{p}^0_2$
$=\text{x}_1\text{p}^0_1+(1-\text{x}_1)\text{p}^0_2$
$=(\text{p}^0_1-\text{p}^0_1)\text{x}_1+\text{p}^0_2$
p = total vapour pressure of the given mixture/ binary solution of the given volatile liquids
p= partial vapour pressure of component 1 (i.e. CHCl3)
p= partial vapour pressure of component 2 (i.e. CH2 Cl2)

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