Question
Using square root table, find the square root,
4955
4955
✓
Answer
On prime factorisation,
4955 is equal to 5 × 991, which means that $\sqrt{4955}=\sqrt{5}\times\sqrt{11}$
The square root of 991 is not listed in the table, it lists the square roots of all the numbers below 100
Hence, we have to manipulate the number such that we get the square root of a number less than 100. This can be done in the following manner.
$\sqrt{4955}=\sqrt{49.55\times100}=\sqrt{49.55}\times10$
Now, we have to find the square root of 49.55
We have, $\sqrt{49}=7$ and $\sqrt{50}=7.071$
Their difference is 0.071
Thus, for the difference of 1 (50 - 49), the difference in the values of the square roots is 0.071
For the difference of 0.55, the difference in the values of the square is,
$0.55\times0.0701=0.03905$
$\therefore\sqrt{49.55}=7+0.3905=7.03905$
Finally, we have
$\sqrt{4955}=\sqrt{49.55}\times10$
$=7.03905\times10=70.3905$
4955 is equal to 5 × 991, which means that $\sqrt{4955}=\sqrt{5}\times\sqrt{11}$
The square root of 991 is not listed in the table, it lists the square roots of all the numbers below 100
Hence, we have to manipulate the number such that we get the square root of a number less than 100. This can be done in the following manner.
$\sqrt{4955}=\sqrt{49.55\times100}=\sqrt{49.55}\times10$
Now, we have to find the square root of 49.55
We have, $\sqrt{49}=7$ and $\sqrt{50}=7.071$
Their difference is 0.071
Thus, for the difference of 1 (50 - 49), the difference in the values of the square roots is 0.071
For the difference of 0.55, the difference in the values of the square is,
$0.55\times0.0701=0.03905$
$\therefore\sqrt{49.55}=7+0.3905=7.03905$
Finally, we have
$\sqrt{4955}=\sqrt{49.55}\times10$
$=7.03905\times10=70.3905$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Verify the following:
$\Big(\frac{-7}{11}+\frac{2}{-5}\Big)+\frac{-13}{22}=\frac{-7}{11}+\Big(\frac{2}{-5}+\frac{-13}{22}\Big)$
→$\Big(\frac{-7}{11}+\frac{2}{-5}\Big)+\frac{-13}{22}=\frac{-7}{11}+\Big(\frac{2}{-5}+\frac{-13}{22}\Big)$
Find (x + y) ÷ (x − y), if
$\text{x}=\frac{2}{5},\text{y}=\frac{1}{2}$
→$\text{x}=\frac{2}{5},\text{y}=\frac{1}{2}$
In the adjacent figure, the bisectors of $\angle\text{A}$ and $\angle\text{B}$ meet in a point P. If $\angle\text{C}=100^\circ$ and $\angle\text{D}=60^\circ$ find the measure of $\angle\text{APB}.$
→A bag contains 3 red balls, 5 black balls and 4 white balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is:
- white?
- red?
- black?
- not red?
Simplify :
(x + y)³ – (x – y)³
After allowing a discount of 20% on the marked price of a lamp, a trader loses 10%. By what percentage is the marked price above the cost price?
Find the amount that David would receive if he invests Rs. 8192 for 18 months at $12\frac{1}{2}\%$ per annum, the interest being compounded half-yearly.
→Solve the following equations :
→$2 m+7=9$
A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of the two smaller cubes are 6 cm and 8 cm , find the edge of the third smaller cube.
Arun took a loan of Rs. 390625 from Kuber Finance. If the company charges interest at 16% per annum, compounded quarterly, what amount will discharge his debt after one year?