Question
Using the formula for squaring a binomial, evaluate the following: $(99)^2$

Answer

Here, we will use the identity $(a + b)^2= a^2+ 2ab + b^2$.
$(99)^2 $
$ =(100-1)^2 $
$ =(100)^2-2 \times 100 \times 1+1^2 $
$ =10000-200+1$
$ =9801 $

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