Question
Using the formula for squaring a binomial, evaluate the following:
$ (999)^2$

Answer

Here, we will use the identity $(a + b)^2= a^2+ 2ab + b^2$.
$ (999)^2 $
$ =(1000-1)^2 $
$ =(1000)^2-2 \times 1000 \times 1+1^2 $
$ =1000000-2000+1 $
$ =998001 $

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