d
Among the hydrides of group \(16\) elements, boiling point of \(H_2O\) is higher than \(H_2S\) (difference in boiling points of \(H_2O\) and \(H_2S\) is around \(200\,^oC\) ) because of strong intermolecular hydrogen bonding. After the decrease in boiling point from \(H_2O\) to \(H_2S\), from \(H_2S\) to \(H_2Te\), it increases due to increase in size of the atoms from \(S\) to \(Te\) which increases the magnitude of van der Waal's forces among the molecules. So, the correct order of boiling points is
                   \(H_2O > H_2Te > H_2Se > H_2S\)