MCQ
Value of x in $\frac{2}{3}\text{x}+ 6 = 12$
- A$-9$
- B$+27$
- ✓$+9$
- D$-27$
$\frac{2}{3}\text{x} + 6 = 12$
$\Rightarrow\frac{2}{3}\text{x}=12-6$
$\Rightarrow\frac{2}{3}\text{x}=6$
$⇒ 2\text{x} = 6\text { x} 3$
$⇒\text{x}=\frac{6×3}{2}$
$⇒\text{x}=9$
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