Question
value of $x$ is
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$2,7-$Dimethyl$\,1 - 2, 6 -$ octadiene $\,\,\overset{{H^+}}{\rightarrow}$ $A$ (Major Product)
The time taken for $A$ to become $1 / 4^{\text {th }}$ of its inital concentration is twice the time taken to become $1 / 2$ of the same. Also, when the change of concentration of $B$ is plotted against time, the resulting graph gives a straight line with a negative slope and a positive intercept on the concentration axis. The overall order of the reaction is . . . . .
$CH _{3} COOH + NaOH \rightarrow CH _{3} COONa + H _{2} O$ $(\Delta H =-55.3\,kJ\,mol ^{-1})$ The enthalpy of ionization of $CH _{3} COOH$ as calculated by the student is $kJ mol ^{-1}$. (nearest integer)
$\mathrm{CO}_2, \mathrm{NO}_2, \mathrm{H}_2 \mathrm{SO}_4, \mathrm{BF}_3, \mathrm{CH}_4, \mathrm{SiF}_4, \mathrm{ClO}_2, \mathrm{PCl}_5,$ $\mathrm{BeF}_2, \mathrm{C}_2 \mathrm{H}_6, \mathrm{CHCl}_3, \mathrm{CBr}_4$