MCQ
Vanadium $(III) $ oxide is a strong
- ADrying agent
- BOxidising agent
- ✓Reducing agent
- DWetting agent
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,C{H_3}}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}}\\
|\\
{C{H_3} - CH - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {C{H_3} - C{H_2} - OH}\limits_{{\rm{III}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,Ph}\\
|\\
{C{H_3} - C - OH}\\
|\\
{\,\,\,\,\,\,\,{\kern 1pt} C{H_3}}
\end{array}}\limits_{{\rm{IV}}} $

$CH_3 -C\equiv C-H$ $\xrightarrow{{C{H_3}MgBr}}$ $CH_4+(A)$ $\mathop {\xrightarrow{{(i)\,C{O_2}}}}\limits_{(ii)\,{H_2}O/{H^ \oplus }} $ $(B)$
$(B)$ will be :