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Total sum of oxygen atoms and \(\pi\)-electrons is \(3+8=11\)
Total number of oxygen atoms \(=3\)
Total number of \(\pi\)-bonds \(=4\)
\(\therefore\) Total number of \(\pi\)-electrons \(=8\)
$CH_3CHO$ $ +$ $CH_3Mgl $ $\xrightarrow {\,\,\,\,}$ $X$ $\xrightarrow {H_2O/H^+}$ $Y$