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Total sum of oxygen atoms and \(\pi\)-electrons is \(3+8=11\)
Total number of oxygen atoms \(=3\)
Total number of \(\pi\)-bonds \(=4\)
\(\therefore\) Total number of \(\pi\)-electrons \(=8\)
$[Figure]$ $\xrightarrow[{(ii){H_2}O}]{{(i)\,{C_2}{H_5}MgBr}}A\xrightarrow{{HCl}}B$