Maharashtra BoardEnglish MediumSTD 9MathsPolynomials2 Marks
Question
Verify that $(x-1)$ is a factor of the polynomial $x^3+4 x-5$.
✓
Answer
Here, $p ( x )= x ^3+4 x -5$
Substituting $x=1$ in $p(x)$, we get
$p(1)=(1)^3+4(1)-5$
$=1+4-5$
$P(1)=0$
$\therefore$ By remainder theorem,
Remainder $=0$
$\therefore(x-1)$ is the factor of $x ^3+4 x -5$.
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