Question
If $1176=2^\text{a}\times3^\text{b}\times7^\text{c},$ find a, b and c.
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Answer
Given that 2, 3 and 7 are factors of 1176. Taking out the LCM of 1176, we get $2^3\times3^1\times7^2=2^\text{a}\times3^\text{b}\times7^\text{c}$ By commparing, we get$\text{a}=3,\ \text{b}=1$ and $\text{c}=2.$
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