MCQ
વિધેય $f(x) = {\log _{3 + x}}({x^2} - 1)$ નો પ્રદેશ મેળવો.
- A$( - 3,\; - 1) \cup (1,\;\infty )$
- B$[ - 3,\; - 1) \cup [1,\;\infty )$
- ✓$( - 3,\; - 2) \cup ( - 2,\; - 1) \cup (1,\;\infty )$
- D$[ - 3,\; - 2) \cup ( - 2,\; - 1) \cup [1,\;\infty )$
==> ${x^2} > 1,$ ==> $x < - 1{\rm{ \,or\, }}x > 1$ and $3 + x > 0$
$\therefore$ $x > - 3$ and $x \ne - 2$
$\therefore$ ${D_f} = ( - 3,\, - 2) \cup ( - 2,\, - 1) \cup (1,\,\infty )$.
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$B=\left\{x \in R : 3^x\left(\sum_{x=1}^{\infty} \frac{3}{10^x}\right)^{x-3} < 3^{-3 x}\right\}$ જ્યાં $[t]$ મહત્તમ પૂર્ણાક વિધેય દર્શાવે છે,તો