MCQ
વિકલ સમીકરણ $\frac{{{d}^{2}}y}{d{{x}^{2}}}+\sqrt{1+{{\left( \frac{dy}{dx} \right)}^{3}}}=0$ ના કક્ષા મેળવો.
- A$1$
- ✓$2$
- C$3$
- D$6$
On squaring, we get ${\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^2} = 1 + {\left( {\frac{{dy}}{{dx}}} \right)^3}$
Obviously the degree is $2$.
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