MCQ
વિકલ સમીકરણ $\frac{{dy}}{{dx}} = \frac{{\left( {1 + x} \right)y}}{{\left( {y - 1} \right)x}}$ નો ઉકેલ મેળવો..
- A$log\ xy + x + y = c$
- B$\log \left( {\frac{x}{y}} \right) + x - y = c$
- C$log\ xy + x -y = c$
- Dએક પણ નહી
$\frac{\mathrm{y}-1}{\mathrm{y}} \mathrm{d} \mathrm{y}=\frac{(1+\mathrm{x})}{\mathrm{x}} \mathrm{d} \mathrm{x}$
$\Rightarrow\left(1-\frac{1}{\mathrm{y}}\right) \mathrm{d} \mathrm{y}=\left(1+\frac{1}{\mathrm{x}}\right) \mathrm{d} \mathrm{x}$
$\Rightarrow(\mathrm{y}-\log \mathrm{y})=(\mathrm{x}+\log \mathrm{x})+\mathrm{c}$
$\Rightarrow \mathrm{x}-\mathrm{y}+\log \mathrm{xy}=\mathrm{c}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.