MCQ
Vinegar is
- A$HCHO$
- B$HCOOH$
- C$C{H_3}CHO$
- ✓$C{H_3}COOH$
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Reaction $- (2): CH_3 -CH = CH -CH_3 \xrightarrow{KMn{{O}_{4}}/NaI{{O}_{4}}}(C)$ $2\,mole$
Product $(B)$ and $(C)$ respectively are