MCQ
Vinegar obtained from sugarcane has
- ✓$C{H_3}COOH$
- B$HCOOH$
- C${C_6}{H_5}COOH$
- D$C{H_3}C{H_2}COOH$
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$\mathrm{C}\mathrm{H}_{3} -\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{C}\left(\mathrm{CH}_{3}\right)_{3} \xrightarrow[\Delta]{{\mathrm{excess} \mathrm{HI}}} \mathrm{C}+\mathrm{D}$
$\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad$(Yellow coloured compound)
Consider the above reaction, the Product $"P"$ is:
the rate of reaction is given by the expression :
$\begin{array}{*{20}{c}}
{{C_6}{H_5} - C - H} \\
{\,\,\,\,\,\,\,\,\,\,||} \\
{\,\,\,\,\,\,\,\,\,\,\,\,O}
\end{array}\xrightarrow{{N{H_2}OH/{H^ \oplus }}}[X]$
$[X] $ will be :