MCQ
Water droplets are coming from an open tap at particular rate. The spacing between a droplet observed at $4^{{th}}\;second$ after its fall to the next droplet is $34.3 \,{m}$. At what rate the droplets are coming from the tap ? (Take $g=9.8\, {m} / {s}^{2}$)
  • $1 \,drop/ second$
  • B
    $2 \,drops / second$
  • C
    $1\, drops / 7 seconds$
  • D
    $3\, drops / 2 seconds$

Answer

Correct option: A.
$1 \,drop/ second$
a
In 4 sec. $1^{\text {st }}$ drop will travel $\Rightarrow \frac{1}{2} \times(9.8) \times(4)^{2}=78.4 m$

$\therefore 2^{\text {nd }}$ drop would have travelled $\Rightarrow 78.4-34.3=44.1 m$.

Time for $2^{\text {nd }}$ drop

$\frac{1}{2}(9.8) t ^{2}=44.1$

$t=3 sec$

$\therefore$ each drop have time gap of $1 sec$

$\therefore 1$ drop per sec

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