Water flows in a streamlined manner through a capillary tube of radius $a$, the pressure difference being $P$ and the rate of flow $Q$. If the radius is reduced to $a/2$  and the pressure increased to $ 2P, $ the rate of flow becomes
  • A$4Q$
  • B$Q$ 
  • C$\frac{Q}{4}$
  • D$\frac{Q}{8}$
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