MCQ
Water flows in a streamlined manner through a capillary tube of radius $a$, the pressure difference being $P$ and the rate of flow $Q$. If the radius is reduced to $a/2$ and the pressure increased to $ 2P, $ the rate of flow becomes
- A$4Q$
- B$Q$
- C$\frac{Q}{4}$
- ✓$\frac{Q}{8}$
