Water is flowing in a pipe of diameter $ 4 cm$ with a velocity $3 m/s. $ The water then enters into a tube of diameter $ 2 cm.$ The velocity of water in the other pipe is .......... $m/s$
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(c)${a_1}{v_1} = {a_2}{v_2}$ ==> $\frac{{{v_2}}}{{{v_1}}} = \frac{{{a_1}}}{{{a_2}}} = {\left( {\frac{{{r_1}}}{{{r_2}}}} \right)^2}$
==> ${v_2} = 3 \times {(2)^2}$ $= 12 m/s$
==> ${v_2} = 3 \times {(2)^2}$ $= 12 m/s$
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