Water is flowing through a tube of non-uniform cross-section ratio of the radius at entry and exit end of the pipe is $ 3 : 2.$ Then the ratio of velocities at entry and exit of liquid is
Medium
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(a) If velocities of water at entry and exit points are $v_1 and v_2$, then according to equation of continuity,
${A_1}{v_1} = {A_2}{v_2}$==> $\frac{{{v_1}}}{{{v_2}}} = \frac{{{A_2}}}{{{A_1}}} = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^2} = {\left( {\frac{2}{3}} \right)^2} = \frac{4}{9}$
${A_1}{v_1} = {A_2}{v_2}$==> $\frac{{{v_1}}}{{{v_2}}} = \frac{{{A_2}}}{{{A_1}}} = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^2} = {\left( {\frac{2}{3}} \right)^2} = \frac{4}{9}$
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