Watt-hour meter measures
Easy
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Effective resistance across $A B$ in the network shown in .......... $\Omega$View Solution
- 2An infinite ladder network is arranged with resistances $R$ and $2 R$ as shown. The effective resistance between terminals $A$ and $B$ isView Solution
- 3The current in the primary circuit of a potentiometer is $0.2\, A$. The specific resistance and cross section of the potentiometer wire are $4\times10^{-7}\,ohm$ $metre$ and $8\times10^{-7}\, m^2$ respectively. The potential gradient will be equal to .............. $V/m$View Solution
- 4For a cell terminal $P.D.$ is $2.2\;V$ when circuit is open and reduces to $1.8\;V$ when cell is connected to a resistance of $R = 5\,\Omega $. Determine internal resistance of cell $(r)$ is then ........ $\Omega$View Solution
- 5To determine the resistance ($R$) of a wire, a circuit is designed below, The $V-I$ characteristic curve for this circuit is plotted for the voltmeter and the ammeter readings as shown in figure. The value of $\mathrm{R}$ is . . . . . . .$\Omega$View Solution
- 6In a meter bridge the point $D$ is neutral point as shown in the figure.View Solution
- 7In the diagram resistance between any two junctions is $R$. Equivalent resistance across terminals $A$ and $B$ isView Solution
- 8View SolutionAssertion : Ohm's law is applicable for all conducting elements.
Reason : Ohm's law is a fundamental law
- 9Four identical cells each having an electromotive force $(e.m.f.)$ of $12\,V$, are connected in parallel. The resultant electromotive force $(e.m.f.)$ of the combination is .............. $V$View Solution
- 10The combination of two identical cells, whether connected in series or parallel combination provides the same current through an external resistance of $2 \,\Omega$. The value of internal resistance of each cell is ............ $\Omega$View Solution