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Structure of Atom — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistryStructure of Atom2 Marks
Question
Wavelengths of different radiations are given below:
$\lambda(\text{A})=300\text{nm},\ \lambda(\text{B})=300\mu\text{m},\ \lambda(\text{C})=3\text{nm},\ \lambda(\text{D})=30\mathring{\text{A}}$
Arrange these radiations in the increasing order of their energies.
✓

Answer

$\text{E}=\text{hv or }=\frac{\text{hc}}{\lambda}\ \text{or E}\propto\frac{1}{\lambda}$
$\lambda(\text{A})=300\text{nm}=300 \times10^{-9}\text{m}\ \text{or}\ =3\times10^{-7}\text{m};$
$\lambda(\text{B})=300\times10^{-6}\text{m}=3\times10^{-4}\text{m}$
$\lambda(\text{C})=3\times10^{-9}\text{m},\lambda(\text{D})=30\times10^{-10}\text{m}=3\times10^{-9}\text{m}$
$\therefore$ Increasing order of energies is:
$\text{B}<\text{A}<\text{C}=\text{D}$

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