9. Hydricarbon — Chemistry STD 11 Science — Question

Kolbe reaction is formally a decarboxylative dimerisation of two carboxylic acids (or carboxylate ions) The overall general reaction is as shown in an image.

After electrolysis alkane is formed at anode along with the release of carbon-dioxide. When potassium acetate $\left(\mathrm{CH}_{3} \mathrm{COO}^{-} \mathrm{K}^{+}\right)$ is used in electrolysis, carbon dioxide is released

along with ethane $\left(\mathrm{H}_{3} \mathrm{C}-\mathrm{CH}_{3}\right)$

$\mathrm{CH}_{3} \mathrm{COO}^{-} \longrightarrow \mathrm{CH}_{3}($ radical $)+\mathrm{CO}_{2}$

$\mathrm{CH}_{3}($ radical $)+\mathrm{CH}_{3}($ radical $) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{6}($ ethane $)$ is release at anode.

Option C is the correct answer.