Question
What happens when 2-bromobutane is being treated with KOH (alcoholic)?

Answer

$\text{CH}_3-\text{CH}-\text{CH}_2-\text{CH}_3+\text{KOH(alc.)}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{Br}\\ \ \ \ _{2-\text{bromobutane}}\\\overrightarrow{\ \ \ \ \ \ \ }\text{ CH}_3-\text{CH}=\text{CH}-\text{CH}_3+\text{KBr}+\text{H}_2\text{O}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ _{\text{But-2-ene}}\\ \ \ \ \ \ \ \ \ \ \ \ \ \ _{\text{But-2-ene will be formed.}}$

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