MCQ
What hybrid orbitals will form the following compound ${H_3}C - CH = CH - C{H_2} - C{H_3}$
- A$sp$ and $s{p^3}$
- ✓$s{p^2}$ and $s{p^3}$
- C$sp$ and $s{p^2}$
- DOnly $s{p^3}$
✓
Answer
Correct option: B.
$s{p^2}$ and $s{p^3}$
(b) $s{p^2}$ and $s{p^3}$
$\mathop {C{H_3}}\limits_{s{p^3}} - \mathop {CH}\limits_{s{p^2}} = \mathop {CH}\limits_{s{p^2}} - \mathop {C{H_2}}\limits_{s{p^3}} - \mathop {C{H_3}}\limits_{s{p^3}} $
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