MCQ
What is final product $Ph - C \equiv CH\xrightarrow[{Hgs{o_4}}]{{dil{H_2}S{O_4}}}\Pr oduct$
- ✓$\,\,\,\begin{array}{*{20}{c}}
O \\ {||\,} \\
{Ph - C - C{H_3}}
\end{array}$ - B$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{Ph - C{H_2} - C - H}
\end{array}$ - C$Ph-CH_2-CH_3$
- D$\,\,\,\begin{array}{*{20}{c}} {OH} \\ {|\,\,\,\,\,\,\,} \\ {Ph - CH - C{H_3}} \end{array}$
