Question
What is limiting molar conductivity ? Explain relation between molar conductivity and concentration of solution with strong electrolyte.
✓
Answer
→ "When the concentration of solution approaches zero, the molar conductivity is known as limiting molar conductivity and is represented by the symbol $\wedge_m^0$
→ Electrolytes which is completely ionize is known as strong electrolyte.
e.g. $KCl , NaCl , MgCl _2, CaCl _2, NaNO _3, KNO _3$ etc.
→ For strong electrolytes, $\wedge_{ m }$increases slowly with dilution and can be represented by the equation : $
\wedge_{ m }=\Lambda^0{ }_{ m }- Ac ^{\frac{1}{2}}
$
→ It can be seen that if we plot $\wedge_{ m }$ against $c ^{\frac{1}{2}}$, we obtain a straight line with intercept equal to $\wedge^0{ }_{ m }$ and slope equal to - A .
→ The value of the constant A for a given solvent and temperature depends on the type of electrolyte.
→ Thus, $NaCl , CaCl _2, MgSO _4$ are known as 1-1, 2-1 and 2-2 electrolytes respectively. Al electrolytes of a particular type have the same value for 'A'.
→ Electrolytes which is completely ionize is known as strong electrolyte.
e.g. $KCl , NaCl , MgCl _2, CaCl _2, NaNO _3, KNO _3$ etc.
→ For strong electrolytes, $\wedge_{ m }$increases slowly with dilution and can be represented by the equation : $
\wedge_{ m }=\Lambda^0{ }_{ m }- Ac ^{\frac{1}{2}}
$
→ It can be seen that if we plot $\wedge_{ m }$ against $c ^{\frac{1}{2}}$, we obtain a straight line with intercept equal to $\wedge^0{ }_{ m }$ and slope equal to - A .
→ The value of the constant A for a given solvent and temperature depends on the type of electrolyte.
→ Thus, $NaCl , CaCl _2, MgSO _4$ are known as 1-1, 2-1 and 2-2 electrolytes respectively. Al electrolytes of a particular type have the same value for 'A'.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
How the following conversions can be carried out?
i. 2-Bromopropane to 1-bromopropane
ii. Chloroethane to butane
iii. Benzene to diphenyl
i. 2-Bromopropane to 1-bromopropane
ii. Chloroethane to butane
iii. Benzene to diphenyl
- E0 value for the Mn3+/Mn2+ couple is positive (+ 1.5V) whereas that of Cr3+/Cr2+ is negative (-0.4 V). Why?
- Transition metals form coloured compounds. Why?
- Complete the following equation:
$\text{2MnO}^{-}_{4}+\text{16H}^{+}+\text{5C}_{2}\text{O}^{2-}_{4}\xrightarrow{\text{ }\ \ \ \ \ \ \ \ \ \ \ \ }$
Write chemical reactions to show that open structure of D-glucose contains the following:
- Straight chain.
- Five alcohol groups.
- Aldehyde as carbonyl group.
Explain the lanthanoid contraction.
Explain the following:
Haloalkanes react with KCN to form alkyl cyanides as main product while AgCN forms isocyanides as the major product.
Haloalkanes react with KCN to form alkyl cyanides as main product while AgCN forms isocyanides as the major product.
(a) $Cu ^{+} X ^{-}$is unstable, why?
(b) Explain the structure of $Mn _2 O _7$ and $MnO _4^{-}$.
→(b) Explain the structure of $Mn _2 O _7$ and $MnO _4^{-}$.
What are haloarenes? How are they classified? Give one method for each of the preparation of nuclear and side chain substituted halorenes.
Determine the osmatic pressure of a solution prepared by dissolving 2.5×10-2g of K2SO4 in 2L of water at 25oC, assuming that it is completely dissociated.
(R=0.0821 L atm K-1 mol-1, Molar mass of K2SO4=174 g moi-1).
Write down three differences between crystalline and amorphous solids.
Explain measurement and calculation of resistance and conductivity of electrolytic solution.