Question
What is oxidation state of Cr in $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$
✓
Answer
Let oxidation state of Cr be ‘x', H is +1, O is -2,
Cl = -1
x + 12 - 12 - 3 = 0
x = 3
Cl = -1
x + 12 - 12 - 3 = 0
x = 3
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