What is the action of (i) H _2 O and (ii) PF _5 on XeF _2 ? - Vidyadip

Question

What is the action of
(i) $H _2 O$ and
(ii) $PF _5$ on $XeF _2$ ?

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Answer

(i) Action of $H _2 O$ (Hydrolysis):
$XeF _2$ undergoes hydrolysis to form $HF$.
$2 XeF _2+2 H _2 O \rightarrow 4 HF +2 Xe + O _2$

(ii) Reaction with $PF _5$ :
$XeF _2$ forms adducts on reaction with $PF _5$.
$XeF _2+ PF _5 \rightarrow XeF _2 \cdot PF _5$

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