Question
What is the current in the circuit shown (Fig. )
✓
Answer
Given, potential difference, V = 2 volt
Let R be the equivalent resistance of the circuit and I be the current flowing through it; then
$R=\left[\left(\frac{1}{2}+\frac{1}{2}\right)^{-1}+(1)\right]$
$R=[1+1]=2 \Omega$
$\therefore I=\frac{V}{R}=\frac{2}{2}=1 \mathrm{~A}$
Let R be the equivalent resistance of the circuit and I be the current flowing through it; then
$R=\left[\left(\frac{1}{2}+\frac{1}{2}\right)^{-1}+(1)\right]$
$R=[1+1]=2 \Omega$
$\therefore I=\frac{V}{R}=\frac{2}{2}=1 \mathrm{~A}$
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