MCQ
What is the effect of increasing pressure on the dissociation of $PC{l_5}$ according to the equation $PC{l_{5(g)}}$ $\rightleftharpoons$ $PC{l_{3(g)}} + C{l_{2(g)}} - x\;cal$
  • Dissociation decreases
  • B
    Dissociation increases
  • C
    Dissociation does not change
  • D
    None of these

Answer

Correct option: A.
Dissociation decreases
(a) $PC{l_5}_{(g)}$ $ \rightleftharpoons $ $PC{l_3}_{(g)} + C{l_2}_{(g)}$

For this reaction $\Delta n = 2 - 1 = 1$

Value of $\Delta n$ is positive so the dissociation of $PC{l_5}$ take forward by decrease in pressure & by increase in pressure the dissociation of $PC{l_5}$ decrease.

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