MCQ
What is the equivalent mass of $IO_4^ - $ when it is converted into ${I_2}$ in acid medium
  • A
    $M/6$
  • $M/7$
  • C
    $M/5$
  • D
    $M/4$

Answer

Correct option: B.
$M/7$
(b) Equivalent mass $ = \frac{{{\rm{Molecular\, weight}}}}{{{\rm{Change\, in \,oxidation\,number\, per\, mole}}}}$

Suppose molecular weight is $M$ Oxidation number of ${I_2}$ in $IO_4^ - $ in Acidic medium i.e., $I \times ( - 8) + 1{e^ - } = + 7$

So eq. wt. $ = M/7$.

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