MCQ
What is the IUPAC name of the following compound?
CH3−CH2−CH2−OH
CH3−CH2−CH2−OH
- APropan-1-ol
- BPropan-2-ol
- CPropane-1-ol
- DEthane-2-ol
Explanation:
In this compound, the number of carbon atoms is 3. So, the parent alkane is propane.
The functional group present is −OH i.e alcohol. −OH is present at the first carbon atom.
Thus the IUPAC name is Propan - 1 - ol.
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the final product $(C)$ is
$(1)$ It is reduced to methyl phenyl carbinol by sodium and ethanol
$(2)$ It is oxidised to benzoic acid with acidified $KMn{O_4}$
$(3)$ It does not undergo iodoform electrophilic substitution like nitration at meta position
$(4)$ It does not undergo iodoform reaction with iodine and alkali