What is the maximum acceleration of the particle doing the $SHM$ $y = 2\sin \left[ {\frac{{\pi t}}{2} + \phi } \right]$ where $2$ is in $cm$
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(b) Comparing given equation with standard equation,
$y = a\sin (\omega t + \phi ),$ we get, $a = 2\,cm,$ $\omega = \frac{\pi }{2}$
$\therefore {A_{max}} = {\omega ^2}A$ $= {\left( {\frac{\pi }{2}} \right)^2} \times 2$ $ = \frac{{{\pi ^2}}}{2}\,cm/{s^2}$.
$y = a\sin (\omega t + \phi ),$ we get, $a = 2\,cm,$ $\omega = \frac{\pi }{2}$
$\therefore {A_{max}} = {\omega ^2}A$ $= {\left( {\frac{\pi }{2}} \right)^2} \times 2$ $ = \frac{{{\pi ^2}}}{2}\,cm/{s^2}$.
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