Question
What is the minimum distance between two objects which can be resolved by a microscope having the visual angle of $30^{\circ}$ when light of wavelength $600 \ nm$ is used?

Answer

$\text { Data : } \theta=30^{\circ}, \lambda=600 \ mm =6 \times 10^{-7} m$
$d_{\text {min }} =\frac{0.61 \lambda}{\tan \theta} $
$=\frac{0.61 \times 6.0 \times 10^{-7}}{\tan 30^{\circ}} m $
$=\frac{3.66 \times 10^{-4}}{0.5774} m$
$ =6.339 \times 10^{-7} m$

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