What is the power dissipated in an ac circuit in which voltage and current are given by $\text{V}=230\sin(\omega\text{t}+\frac{\pi}{2})$ and $\text{I}=10\sin\omega\text{t}?$
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Power dissipated P $=\frac{1}{2}\text{V}_0\text{I}_0\cos\varphi$
Here, $\text{V}_0=230\text{V},\text{I}_0=10\text{A},\varphi=\frac{\pi}{2}$
$\therefore\text{P}=\frac{1}{2}\times230\times10\cos\frac{\pi}{2}=0$
Here, $\text{V}_0=230\text{V},\text{I}_0=10\text{A},\varphi=\frac{\pi}{2}$
$\therefore\text{P}=\frac{1}{2}\times230\times10\cos\frac{\pi}{2}=0$
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