What is the pressure in $atm$ on a swimmer $10\; m$ below the surface of a lake?
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$h=10 m$ and $\rho=1000 kg m ^{-3} .$ Take $g =10 m s ^{-2}$
$P =P_{ a }+\rho g h$
$=1.01 \times 10^{5} Pa +1000 kg m ^{-3} \times 10 m s ^{-2} \times 10 m$
$=2.01 \times 10^{5} Pa$
$\approx 2 \,atm$
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