Question
What is the smallest positive phase constant which is equivalent to $7.5\pi?$
$\text{y}=\text{A}\sin (\text{kx}-\omega\text{t}+\phi)$
Here, A is the amplitude, k is the wave nunumber, $\omega$ is the angular frequency and $\phi$ is the initial phase. The argument of the sine is a phase, so the smallest positive phase constant should be.$\sin(7.5\pi)=\sin (3\times2\pi+1.5\pi)$
$=\sin (1.5\pi)$
Therefore, the smallest positive phase constant is $1.5 \pi.$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.