Question
What is the value of $\sqrt[3]{64}-\frac{1}{\sqrt[3]{64}}?$

Answer

$\begin{array}{l}\sqrt[3]{64}-\frac{1}{\sqrt[3]{64}} \\ \because \text { Cube root of } 64=\sqrt[3]{64}=\overline{4 \times 4 \times 4}=4 \\ \therefore 4-\frac{1}{4}=\frac{15}{4}~ \text { or }~ 3 \frac{3}{4}\end{array}$

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