What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of $10cm$ ......... $m/s$ (Take $g = 9.8\,m/{s^2})$
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(b)$v = \sqrt {2gh} = \sqrt {2 \times 9.8 \times 0.1} = \sqrt {1.96} = 1.4\,m/s$
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