What volume of ethyl alcohol and water must be mixed together to prepare $250\ ml$ of $60 \%$ volume by volume solution of alcohol in water.
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$60 \%$ by volume of alcohol solution means, each $100\ ml$ of solution will have $60\ ml$ ethyl alcohol.
So, $250\ ml$ of solution will have $=\Big(\frac{60}{100}\Big)\times250=150\text{ml}$ of ethyl alcohol Hence in a $250\ ml$ solution of $60 \%$ by volume of alchohol and water, alcohol should be $150\ ml$ and water should be $100\ ml$.
So, $250\ ml$ of solution will have $=\Big(\frac{60}{100}\Big)\times250=150\text{ml}$ of ethyl alcohol Hence in a $250\ ml$ solution of $60 \%$ by volume of alchohol and water, alcohol should be $150\ ml$ and water should be $100\ ml$.
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