MCQ
What will be $C-H$ bond enthalpy if 

$CH_4(g) +2O_2(g)  \rightarrow  CO_2(g)+2H_2O(l)\,;$  $\Delta H= -890 \,kJ$

$CO_2(g)  \rightarrow  C($graphite$) + O_2(g) \,;$   $\Delta H= 393 \,kJ$

$2H_2O(l)  \rightarrow  2H_2(g) + O_2(g) \,;$  $\Delta H= 571 \,kJ$

$2H_2(g) \rightarrow  4H(g)\, ;$  $\Delta H= 871\, kJ$

$C($graphite$)  \rightarrow  C(g)\, ;$  $\Delta H= 716\, kJ$

  • A
    $1663.39\, kJ/mol$
  • $415.25\, kJ/mol$
  • C
    $917.3\, kJ/mol$
  • D
    $215.5\, kJ/mol$

Answer

Correct option: B.
$415.25\, kJ/mol$
b
$\mathrm{CH}_{4}(\mathrm{g})+2 \mathrm{O}_{2}(\mathrm{g}) \longrightarrow \mathrm{CO}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\ell)$

$\Delta \mathrm{H} =-890 \,\mathrm{kJ}$

$\mathrm{CO}_{2}(\mathrm{g}) \longrightarrow \mathrm{C}_{( \text {graphite) } }+\mathrm{O}_{2}(\mathrm{g})  \text { : } $

$\Delta \mathrm{H} =393 \,\mathrm{kJ} $

$2{{\text{H}}_2}{\text{O}}(l) \to 2{{\text{H}}_2}({\text{g}}) + {{\text{O}}_2}({\text{g}}){\text{  : }}$

$\Delta \mathrm{H} =571\, \mathrm{kJ}$

$2 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow 4 \mathrm{H}(\mathrm{g}): \quad \Delta \mathrm{H}=871\, \mathrm{kJ}$

$\mathrm{C}_{(\text {graphite })} \longrightarrow \mathrm{C}(\mathrm{g}) ; \quad \Delta \mathrm{H}=716\, \mathrm{kJ}$

$\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_$

$\mathrm{CH}_{4}(\mathrm{g}) \longrightarrow 4 \mathrm{H}(\mathrm{g})+\mathrm{C}(\mathrm{g}) ; \Delta \mathrm{H}=1661$

$50\, \mathrm{C}-\mathrm{H}=\frac{1661}{4}=415.25$

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