MCQ
What will be number of electrons in 1 kg electron?
- A$6.022 \times 10^{23}$
- ✓$\frac{10^{31}}{9.1}$
- C$\frac{6.029}{91} \times 10^{54}$
- D$\frac{1 \times 10^8}{9.1 \times 6.022}$
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[Given : Specific heat of water $=4.18\, \mathrm{~J} \,\mathrm{~g}^{-1}\, \mathrm{~K}^{-1}$
Density of water $=1.00\, \mathrm{~g}\, \mathrm{~cm}^{-3}$ ]
(Assume no volume change on mixing)