MCQ
What will be the amount of heat evolved by burning $0.4$ $moles$ of methane ?
(Given heats of formation of $CH_4, CO_2$ and $H_2O$ are $-75, -400$ and $-240\, kJ\, mol^{-1}$ respectively) .....$ kJ$
  • A
    $805.8$
  • B
    $398.8$
  • $322$
  • D
    $640.4$

Answer

Correct option: C.
$322$
c
$\Delta \mathrm{H}_{\mathrm{C}}\left(\mathrm{CH}_{4}\right) =\Delta \mathrm{H}_{\mathrm{f}}\left(\mathrm{CO}_{2}\right)+2 \Delta \mathrm{H}_{\mathrm{f}}\left(\mathrm{H}_{2} \mathrm{O}\right) $

$=-400+2(-240)-(-75) =-805 \,\mathrm{kJ} $

$1\, \text { mole } \rightarrow  805\, \mathrm{kJ} $

$\Rightarrow  0.4 \text { mole } \rightarrow ? $

$ 805 \times 0.4=322 \,\mathrm{kJ}$

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